The owner of a coffee shop recorded the number of customers who came into his café each hour in a day. The results were 14, 10, 12, 9, 17, 5, 8, 9, 14, 10, and 11
1. What is the least value of the data?
2. What is the greatest value of the data?
3. Arrange the data in ascending order.
4. Lower Quartile=_____
5. Upper Quartile=_____
6. Interquartile range=_____
Answers
Given : The owner of a coffee shop recorded the number of customers who came into his café each hour in a day.
The results were 14, 10, 12, 9, 17, 5, 8, 9, 14, 10, and 11
To Find :
1. What is the least value of the data?
2. What is the greatest value of the data?
3. Arrange the data in ascending order.
4. Lower Quartile=_____
5. Upper Quartile=_____
6. Interquartile range=_____
Solution :
The results were 14, 10, 12, 9, 17, 5, 8, 9, 14, 10, and 11
Arrange the data in ascending order.
5, 8, 9, 9, 10, 10, 11 , 12, 14, 14, 17
least value of the data = 5
greatest value of the data = 17
terms = 11 hence
Lower Quartile= (11 + 1)/4 = 3 rd term which is 9
Upper Quartile= 3(11 + 1)/4 = 9th term which is 14
Interquartile range= Upper Quartile - Lower Quartile
= 14 - 9
= 5
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Given:-
The owner of a coffee shop recorded the number of customers who came into his café each hour in a day. The results were 14, 10, 12, 9, 17, 5, 8, 9, 14, 10, and 11.
________________________
Solution:-
The results were 14, 10, 12, 9, 17, 5, 8, 9, 14, 10, and 11
Arrange the data in ascending order.
5, 8, 9, 9, 10, 10, 11 , 12, 14, 14, 17
→ least value of the data = 5
→ greatest value of the data = 17
→ terms = 11
hence,
Lower Quartile = (11 + 1)/4 = 3 rd term which is 9
Upper Quartile= 3(11 + 1)/4 = 9th term which is 14
Interquartile range = Upper Quartile - Lower Quartile
= 14 - 9
= 5