Question

The owner of a coffee shop recorded the number of customers who came into his café each hour in a day. The results were 14, 10, 12, 9, 17, 5, 8, 9, 14, 10, and 11

1. What is the least value of the data?
2. What is the greatest value of the data?
3. Arrange the data in ascending order.
4. Lower Quartile=_____
5. Upper Quartile=_____
6. Interquartile range=_____

need your help​

Answer 1

Given:  

Data: 14, 10, 12, 9, 17, 5, 8, 9, 14, 10, 11

To Find :    

1. What is the least value of the data?  

2. What is the greatest value of the data?  

3. Arrange the data in ascending order.  

4. Lower Quartile = _____  

5. Upper Quartile = _____  

6. Interquartile range = _____

​Solution :

 Arrange the given data in ascending order.

5, 8, 9, 9, 10, 10, 11, 12, 14, 14, 17

The least value of the data = 5

The greatest value of the data = 17

Since the number of terms (n) = 11

Lower Quartile = (n + 1) × 1/4 = (11 + 1) × 1/4 = 3rd term

So, Lower Quartile = 9

Upper Quartile = (n + 1) × 3/4 = (11 + 1) × 3/4 = 9th term

So, Upper Quartile = 14

Interquartile range = Upper Quartile - Lower Quartile = 14 - 9

So, Interquartile range = 5