Math, asked by manish25082, 8 months ago

The owner of the Good Deals Store opens a new store across town. For the new store, the owner estimates that, during business hours, an average of 90 shoppers per hour enter the store and each of them stays an average of 12 minutes. The average number of shoppers in the new store at any time is what percent less than the average number of shoppers in the original store at any time? (Note: Ignore the percent symbol when entering your answer. For example, if the answer is 42.1%, enter 42.1)​

Answers

Answered by Anonymous
39

Answer:

Solution:-

According to the original information given,the estimated number of shoppers in the original store at any time Is 45.

In the Question, it states that

In the New store, the manager estimates that an average of 90 shoppers per hour enter the store.

Which is equivalent to 1.5 shoppers per minute.

By little law's,

N = r

T = (1.5)(12) = 18

we set,

= 45 - 18

= 45× 100

= 60

The Final Answer is B.

______________________

Hope it will be helpful :)


Anonymous: -_-
Anonymous: nothing
Answered by CunningKing
3

QUESTION :-

The owner of the Good Deals Store opens a new store across town. For the new store, the owner estimates that, during business hours, an average of 90 shoppers per hour enter the store and each of them stays an average of 12 minutes. The average number of shoppers in the new store at any time is what percent less than the average number of shoppers in the original store at any time? (Note: Ignore the percent symbol when entering your answer. For example, if the answer is 42.1%, enter 42.1)​

SOLUTION :-

♠ According to the original information given, the estimated average number of shoppers in the original store at any time (x) is 45.

♠ In the question, it states that, in the new store, the manager estimates that an average of 90 shoppers per hour (60 minutes) enter the store, which is equivalent to 1.5 shoppers per minute (s).

♠ The manager also estimates that each shopper stays in the store for an average of 12 minutes (t). Thus, by Little's law, there are, on average, x = s × t

⇒x = 1.5 × 12

⇒x = 18

Hence, there are 18 shoppers at any time in the new store.

\rule{250}2

Now,

percentage of shoppers = \sf{\dfrac{45-18}{45}\times 100=\dfrac{27}{45}\times 100=\dfrac{2700}{45}=60\ \%}

Therefore, the answer is 60 %.  

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