Question

The owner of the Good Deals Store opens a new store across town. For the new store, the owner estimates that, during business hours, an average of 90 shoppers per hour enter the store and each of them stays an average of 12 minutes. The average number of shoppers in the new store at any time is what percent less than the average number of shoppers in the original store at any time? (Note: Ignore the percent symbol when entering your answer. For example, if the answer is 42.1%, enter 42.1)
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Answer 1

N = 45

average no. of shoppers = 90

Shoppers per hour = 60

no.of shoppers/ time = 90/60 = 1.5 shoppers per min

r = 1.5

T (time) = 12 mins

So using formula

N = rt = 1.5 × 12 = 18

So to calculate %

=

$\frac{45 - 18}{45} \times 100$

= 60

hence 60 % less than average no. of shoppers in the orginal store .

(this question is easy.)

Answer 2

Answer:

N = 45

average no. of shoppers = 90

Shoppers per hour = 60

no.of shoppers/ time = 90/60 = 1.5 shoppers per min

r = 1.5

T (time) = 12 mins

So using formula

N = rt = 1.5 × 12 = 18

So to calculate %

=

\frac{45 - 18}{45} \times 100

45

45−18

×100

= 60

hence 60 % less than average no. of shoppers in the orginal store .

(this question is easy.)

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