Question

the oxidation no. of c atom in ch2cl2 and ccl4​

Answer 1

Explanation:

Oxidation No of C in CH2Cl

x + 2(-1) + (-1) = 0

x - 2 - 1 = 0

x - 3 = 0

x = 3

Oxidation No of C in CCl4

x + 4(-1) = 0

x = 4