Question

The oxidation no. of [CuCl2 {O=C(NH2 ) 2 }2 ] is

Answer 1

Answer:

+2

Explanation:

Let the oxidation no. of Cu be x

oxidation no. of chlorine= -1

oxidation no. of O=C(NH2 ) 2 = 0

=> X + 2(-1) + 2(0) = 0

=> X = +2