The oxidation number of C in CH₄, CH₃Cl, CH₂Cl₂, CHCl₃ and CCl₄ is respectively–
(a) + 4, – 2, 0, + 2, + 4
(b) + 2, 4, 0, – 2, – 4
(c) 4, 2, 0, – 2, – 4
(d) 0, 2, – 2, 4, 4
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b is the answer I think so
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