Question

The Oxidation number of c in sucrose

Answer 1

Answer:

            0

Explanation:

Molecular formula of sucrose =C  12 H  22 O 11

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Overall charge on sucrose =0

Oxidation no. of oxygen in sucrose =−2

Oxidation no. of hydrogen in sucrose =+1

Let the oxidation no. of carbon be x.

Sum of oxidation no. of atoms = overall charge on atom

⇒12×x+22×(+1)+11×(−2)=0

⇒12x+22−22=0

⇒12x=0

⇒x=0

Hence, the oxidation number of carbon in sucrose is 0.