Chemistry, asked by sudipa92, 1 year ago

The oxidation number of carbon in C12H22O11 is(A)0(B)+22(C)+6(D)-6​

Answers

Answered by Anonymous
4

C12H22O11

let oxidation number of carbon be x

x12+22-22=0

x=0

oxidation number of carbon in C12H22O11 is 0

hope it helps mark me as brainliest ..

Answered by yojas95
0

Answer:

I don't know gand marao

Similar questions