Question

The oxidation number of Cr in [Cr(NH3)6]Cl3 is

Answer 1

It can be calculated as follows.

First of all, write individual charges on the elements present. In this case let's take Cr as x and Cl is in -1 while NH3 is 0.

Now check the total charge on the compound,here it is +1.

Now equate the sum of the individual charges of the elements multiplied to the no. of ions to the total charge on the compound.

Which gives,  x+(4*0)+(2*-1)=+1

That gives x=+3.

Hope this helps.

Answer 2

Answer:

+3 is the answer as ammonia has 0 oxidation no. and Cl has -1