Question

The oxidation number of 'Fe'in K4[Fe(CN)6] is-
a) +6
b) +4
c) +3
d) +2​

Answer 1

Answer:The answer should be + 2.

Answer 2

Answer:

+ 2

d. option is correct .

Explanation:

Given :

Compound :

K₄ [ Fe ( CN )₆ ]

We have to calculate O.N. of Fe :

We know :

O.N. of K and CN are + 1 and - 1 respectively.

Let O.N. of Fe be x :

+ 4 + x + ( - 6 ) =  0  [ Net charge on compound is zero ]

4 + x -  6 = 0

x - 2 = 0

x = + 2 .

Therefore , O.N. of Fe is + 2 in K₄ [ Fe ( CN )₆ ].