The oxidation number of manganese atom and the number of electrons in d sub shell of manganese ion in Mno2 is __&__ ?
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oxidation state is 2 and electrons in d shell is 5
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The oxidation number of manganese atom and the number of electrons in d sub-shell of manganese ion in MnO2 are +4 and 3 respectively.
- In MnO2, there are 2 oxygen atoms and their oxidation no is -2 each.
- So, the oxidation no of Mn becomes +4.
- The ground state electronic configuration of Mn can be written as:
Mn (25) = 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d5
- The electronic configuration for +4 oxidation state of manganese can be written as:
Mn (+4) = 1s2, 2s2, 2p6, 3s2, 3p6, 3d3
- So, there are three (3) d-electrons in MnO2.
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