Chemistry, asked by NANDUprasantham, 8 months ago

The oxidation number of manganese atom and the number of electrons in d sub shell of manganese ion in Mno2 is __&__ ?​

Answers

Answered by shreyu2103
6

Answer:

oxidation state is 2 and electrons in d shell is 5

Answered by Jasleen0599
1

The oxidation number of manganese atom and the number of electrons in d sub-shell of manganese ion in MnO2 are +4 and 3 respectively.​

- In MnO2, there are 2 oxygen atoms and their oxidation no is -2 each.

- So, the oxidation no of Mn becomes +4.

- The ground state electronic configuration of Mn can be written as:

Mn (25) = 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d5

- The electronic configuration for +4 oxidation state of manganese can be written as:

Mn (+4) = 1s2, 2s2, 2p6, 3s2, 3p6, 3d3

- So, there are three (3) d-electrons in MnO2.

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