the oxidation number of one shulphur atom in na2s2o3
Answers
Answered by
4
Total oxidation number = 0
2(Na) + 2(S) + 3(O) = 0
2(+1) + 2(S) + 3(-2) = 0
2 + 2(S) - 6 = 0
2(S) = +4
S = +2
#Answered@C29
#PlsMARK
Similar questions