Chemistry, asked by harsha7826, 11 months ago

the oxidation number of one shulphur atom in na2s2o3

Answers

Answered by Anonymous
4

Total oxidation number = 0

2(Na) + 2(S) + 3(O) = 0

2(+1) + 2(S) + 3(-2) = 0

2 + 2(S) - 6 = 0

2(S) = +4

S = +2

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