Question

The oxidation number of Pb in Pb3O4 is :
A) + 2/3
B) +4
) +
D) +2
3​

Answer 1

by taking pb as x oxidation no.

3x+(-2)(4)=0

hence x=+8/3

Answer 2

$\huge\underline\blue{\sf Answer:}$

Let oxidation number of Pb is = x

And we know that

Oxidation number of Oxygen is = -2

So,

$\large\implies{\sf 3×x+4×(-2)=0 }$

$\large\implies{\sf x=+\frac{8}{3} }$

$\large{\sf Pb_3O_4}$ is not exist at this form it exist as $\large{\sf PbO\:and\:PbO_2 }$ and their Oxidation number is in ratio of 2:1