Question

The oxidation number of Pd in K2 [ PdCl4 ] is 

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Answer 1

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Answer 2

Given:

The given complex is $K_2[PdCl_4]$.

To find:

The oxidation number of Pd.

Solution:

The given complex is $K_2[PdCl_4]$.

Let the oxidation number of Pd be x.

The charge on potassium is +1 and the charge of chloride is -1.

The overall charge of the compound is 0.

Hence we can write-

$x + 1 \times 2 + ( - 1) \times 4 = 0 \\ x + 2 - 4 = 0 \\ x = + 2$

The value of x is +2.

Hence the charge of Pd is +2.