the oxidation number of phosphorous in Ba(H2PO2)2 is
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Ba(H2PO2)2 dissociates into Ba^+2 and (H2PO2)^-1. The O.S. of P in Ba(H2PO2)2 is +1. Let the oxidation state of p be x. Here hydrogen has +1 oxidation state because it is behaving like an electropositive(metal) element in presence of more electronegative elements (or non-metals) like P,O.
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Ba(H2PO2)2 dissociates into Ba^+2 and (H2PO2)^-1. The O.S. of P in Ba(H2PO2)2 is +1. Let the oxidation state of p be x. Here hydrogen has +1 oxidation state because it is behaving like an electropositive(metal) element in presence of more electronegative elements (or non-metals) like P,O.
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Answer:+1
Explanation:
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