Physics, asked by Shivbardhan59136, 18 days ago

the oxidation number of sodium per oxide?​

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Answered by devansh8796
0

Answer:

Explanation:

For your sodium peroxide we have Na2O2 . Now sodium generally has an oxidation state of +I in its salts, and it does so here. Thus 1+1+2×Oxidation number of oxygen in peroxide=0 . Clearly, Oxidation number of oxygen in peroxide=−1 .

Answered by adityarajemalave100
0

x^{2} \int\limits^a_b {x} \, dx \neq

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