Question

The oxidation number of sulphur in H2S2O7 and iron in K4Fe(CN)6 is respectively​

Answer 1

Answer:

+6 and +2

Explanation:

See, The 100% correct/aacurate method to find oxidation number is by structure.

But we can do it mathematically, by making some assumptions like there is no peroxide linkage etc. in this case it turns out the assumptions are correct so I would explain both ways:

Pre-requisite Knowledge:

The Sum of formal charge(oxidation number) of all atoms in a compound is equal to the total charge on it.

1) Using Structure [Attached below]:

In the structure we check partial charges on atoms, here on sulphur we have 6 * delta positive charge as it is surrounded by 6 bounds with oxygen which is more electronegative than Sulphur and pulls electron partially towards it from sulphur.

and thus as Oxidation number is formal charge we say Sulphur is in +6 oxidation state.

2) Using Formula and Analytical Method:

In H₂S₂O₇, we let the oxidation number of S be x

We know Oxidation number of H , and O are (generally) 1 and -2  [ this is the assumption here , which makes this method unreliable sometimes, here it is correct]

So 2+2x+(-2)*7 = 0

=> 2+2x-14=0

=>2x=12

=>x=+6

=> The oxidation number of S in H₂S₂O₇ is +6

Now K₄[Fe(CN)₆] is a coordination compound and Fe(CN)₆ is the coordination sphere and the compound splits as 4K⁺ and [Fe(CN)₆] ⁴⁻ and now we see the oxidation number of CN which is -1, and so we let the Oxidation number of Fe be x, so x+6(-1) = -4 => x=+2

so we can say the oxidation number of Fe in this compound is +2

So the answer is +6 and +2 respectively

Hope it helps!

Thank You

Answer 2

${\huge{\underline{\large{\mathbb{\red{ ᥫ᭡KABIR♡~}}}}}}$

+6 and +2

Explanation:

See, The 100% correct/aacurate method to find oxidation number is by structure.

But we can do it mathematically, by making some assumptions like there is no peroxide linkage etc. in this case it turns out the assumptions are correct so I would explain both ways:

Pre-requisite Knowledge:

The Sum of formal charge(oxidation number) of all atoms in a compound is equal to the total charge on it.

1) Using Structure [Attached below]:

In the structure we check partial charges on atoms, here on sulphur we have 6 * delta positive charge as it is surrounded by 6 bounds with oxygen which is more electronegative than Sulphur and pulls electron partially towards it from sulphur.

and thus as Oxidation number is formal charge we say Sulphur is in +6 oxidation state.

2) Using Formula and Analytical Method:

In H₂S₂O₇, we let the oxidation number of S be x

We know Oxidation number of H , and O are (generally) 1 and -2  [ this is the assumption here , which makes this method unreliable sometimes, here it is correct]

So 2+2x+(-2)*7 = 0

=> 2+2x-14=0

=>2x=12

=>x=+6

=> The oxidation number of S in H₂S₂O₇ is +6

Now K₄[Fe(CN)₆] is a coordination compound and Fe(CN)₆ is the coordination sphere and the compound splits as 4K⁺ and [Fe(CN)₆] ⁴⁻ and now we see the oxidation number of CN which is -1, and so we let the Oxidation number of Fe be x, so x+6(-1) = -4 => x=+2

so we can say the oxidation number of Fe in this compound is +2

So the answer is +6 and +2 respectively

Hope this helps you ❤❤