Question

the oxidation number of sulphur in K2 S2 o8 is​

Answer 1

Explanation:

k2s2o8

oxidation number is +2 on k2,

-16 on o8,

let 2x be on s2

2+2x+(-16)=0

=2x=16/8

=x=8/2

=x=4

so oxidation number of sulphur is +4.

hope it helps!