Question

The oxidation number of sulphur in s8o8^_2

Answer 1

Process to find Sulphur's oxidation number  in S₈O₈²⁻ is given below.

Let the O.N. (oxidation number) of sulphur be 'x'.

∴ 8x + 8(-2) = -2

⇒ 8x - 16 = -2

⇒ 8x  = 16 - 2

⇒ 8x  = 14

⇒ x  = $\frac{14}{8}$

∴ O.N. (oxidation number) of sulphur in S₈O₈²⁻ =  $\frac{14}{8}$