Question

The oxidation number of sulphur in sulphuric acid H2SO4 is

Answer 1

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Answer 2

Explanation:

In sulphuric acid, that is, $H_{2}SO_{4}$ the charge on hydrogen is positive 1, and charge on oxygen is negative 2.

Since there are two hydrogen atoms therefore, net positive charge will be number of atoms $\times$ charge on each positive atom.

Thus, total positive charge = 2 $\times$ +1 = +2

Similarly, net negative charge wiil be number of atoms $\times$ charge on each negative atom.

Thus, total negative charge =  4 $\times$ -2 = -8

As the overall sulphuric acid molecule is neutral so, the net charge on molecule will be zero. Therefore, calculate oxidation number of sulphur as follows.

               +2 + S + (-8) = 0

                   S - 6 = 0

                    S = +6

Hence, we can conclude that the oxidation number of sulphur in sulphuric acid is +6.