Chemistry, asked by salonidhadve, 9 hours ago

The oxidation numbers of sulphur in S8, S2F2 and H2S are respectively :

(A) 0, +1, -2
(B) +2, +1, -2
(C) 0, +1, +2
(D) -2, +1, -2​

Answers

Answered by nishasamrooth06
0

Answer:

0,+1 and −2

Oxidation number of sulphur in S

8

is 0.

Oxidation number of F is -1 so oxidation number of sulphur in S

2

F

2

is +1.

Oxidation number of H is +1 so oxidation number of sulphur in H

2

S is -2.

Answered by XxLonelyArmyGirlxX
1

Answer:

(0), (+1) & (-2)

Reason:

Oxidation number of sulphur in S⁸ is 0.

Oxidation number of F is -1 so oxidation number of sulphur in S²F² is +1.

Oxidation number of H is +1 so oxidation number of sulphur in H²S is -2.

Explanation:

Hope this helps you unnie ❣️

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