Chemistry, asked by Riasingh3648, 1 year ago

The oxidation of iodide ion by peroxydisulfate ion is described by the equation

Answers

Answered by Anonymous
1
) This work was supported by the Office of Naval Research and the Atomic Energy Commission. It is based in part on a dissertation submitted by A. Haim to the Graduate School of the University of Southern California in partial fulfillment of the requirements for the Degree of Doctor of Philosophy.(2)(a) Paper I, LR Thompson and WK Wilmarth, J. Phys. Chew., 66, 5 (1952).(b) Paper 11, WK Wilmarth, H. Graff and ST Gustin, THIS JOURNAL, 18, 2683 (1956).
Answered by Anonymous
10

The oxidation of iodide ion by peroxydisulfate ion is described by the equation: 3 I− (aq) + S2O82− (aq)  I3− (aq) + 2 SO42− (aq).

Similar questions