the oxidation state of chromium in K2 cr2 O7
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the oxidation state of chromium in K2 cr2 O7 is +6
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Let the oxidation number of Cr be X
ON of K = +1
ON of O = -2
Therefore,
(2×1)+2x+(7×-2) =0
==> 2+2x-14 = 0
==> 2x-12 = 0
==> 2x = 12
==> x = +6☑️☑️
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