the oxidation state of lin H4lO6- is
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Let oxidation state of I in H4IO6− is x.
Since the overall charge on the complex is −1, the sum of oxidation states of all elements in it should be equal to −1.
Therefore, 4+x−12=−1 (Here, oxidation state of H is +1 and oxygen is -2)
or, x=7
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