Social Sciences, asked by RjRahulSankhyan, 4 months ago

the oxidation state of lin H4lO6- is​

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Answered by Anonymous
0

Answer:

Let oxidation state of I in H4IO6− is x.

Since the overall charge on the complex is −1, the sum of oxidation states of all elements in it should be equal to −1.

Therefore, 4+x−12=−1 (Here, oxidation state of H is +1 and oxygen is -2)

or, x=7

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