The oxidation state of Mo in its oxo – complex species
[Mo2O4 (C2H4)2 (H2O)2]
2– is
1) +5 2) +4 3) +3 4) +2
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Answer:
+3, The oxidation state of Mo in its oxo-complex species is +3
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Hyy Dude
Let the oxidation number of molybdenum (Mo) be x.
Oxidation number of H2o2 = C2HA = 0, O = - 2
In [ M02O4 ( C2HA) 2 ( H2o2]) ² ¯
2x+4×(−2)+2×0+0=−2
2x−8=−2 orx=+3
The oxidation state of molybdenum in its oxo complex species
Mo2O4 ( C2H4) 2 (H2o2)] ²¯ is +4.
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