Chemistry, asked by preetham002, 11 months ago

The oxidation state of Mo in its oxo – complex species

[Mo2O4 (C2H4)2 (H2O)2]

2– is

1) +5 2) +4 3) +3 4) +2



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Answers

Answered by Anonymous
2

Answer:

+3, The oxidation state of Mo in its oxo-complex species is +3

Answered by llxdevilgirlxll
6

Hyy Dude

Let the oxidation number of molybdenum (Mo) be x.

Oxidation number of H2o2 = C2HA = 0, O = - 2

In [ M02O4 ( C2HA) 2 ( H2o2]) ² ¯

2x+4×(−2)+2×0+0=−2

2x−8=−2 orx=+3

The oxidation state of molybdenum in its oxo complex species

Mo2O4 ( C2H4) 2 (H2o2)] ²¯ is +4.

Hope it's helps you

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