Chemistry, asked by sai488, 1 year ago

the oxidation state of Nitrogen in dinitrogen trioxide is

Answers

Answered by Anonymous
3
The oxidation state of nitrogen in Di nitrogen tri oxide is 3.
N2O3
Implies 2X + 3(-2) =.0
2X = 6
X. = 3.

Therefore it is 3.
Hope my answer is useful to you.
Answered by itemderby
0

Explanation:

Formula of dinitrogen trioxide is N_{2}O_{3}.

It is known that oxidation state of oxygen atom is -2. The overall charge on dinitrogen trioxide is zero.

Let the oxidation state of nitrogen be x. Therefore, calculate the oxidation state of nitrogen in dinitrogen trioxide as follows.

                          2x + 3(-2) = 0

                          2x -6 = 0

                           2x = 6

                            x = \frac{6}{2}

                            x = 3

Thus, we can conclude that oxidation state of nitrogen in dinitrogen trioxide is +3.

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