Science, asked by anukulajohn, 7 months ago

The oxidation state of phosphorus in Ba(H2PO2)2 is​

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Answered by nandini0594
1

Answer:

HERE IS UR ANSWER:-

Explanation:

In Ba(H2PO2)2, oxidation number of Ba is +2. Therefore

H2PO−2:2×(+1)+x+2×(−2)=−1

⇒x=+1

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