The oxidation state of phosphorus in Ba(H2PO2)2 is
Answers
Answered by
1
Answer:
HERE IS UR ANSWER:-
Explanation:
In Ba(H2PO2)2, oxidation number of Ba is +2. Therefore
H2PO−2:2×(+1)+x+2×(−2)=−1
⇒x=+1
Similar questions