Question

the oxidation state of the molybdenum in its complex species . [ Mo2O4 ( C2H4 )2 (H2O)2] 2 ^-.

Answer 1

The maxm. CN can be 6.

Here it is 5.

Hence oxidation state for Mo would be:

2x +2*-1 + 0 = – 2

x = 0

Hence the student can simply calculate with the support of the right formula in a fine manner even it can provide better ideas in it.