the oxidation state of the most electronegative elements in rhe product of the reaction ,Ba02 with dilute H2SO4 are :-
a ) 0 and -1.
b) - 1and -2.
c) -2 and 0.
d) -2and -1.
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Answered by
5
answer -
the reaction is
BaO2^-4 + H2SO4^-2 ----------> BaSO4^-2 + H2O2 ^-1.
most electronegative elements is 0.
the O.S of O in the products are -2 and -1
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the reaction is
BaO2^-4 + H2SO4^-2 ----------> BaSO4^-2 + H2O2 ^-1.
most electronegative elements is 0.
the O.S of O in the products are -2 and -1
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HEY MATE HERE IS YOUR ANSWER
D. - 2 AND - 1
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D. - 2 AND - 1
THANKS HOPE IT WILL HELP YOU
BE BRAINLY
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