English, asked by Xzits11, 22 days ago

The oxidation state shown by an element of the second period is -2. How many electrons are there in the outer most shell of this element?​

Answers

Answered by kritjangid07
0

Explanation:

A die has the shape of a tetrahedron. The lour faces are numbered 1, 2, 3 and 4. The die is thrown on the table. The probabilities of each of the four faces finishing liat on the table are as shown. - 1 2 3 1 Probability eila ine b Copy the table and till in the four empty boxes with the probabilities changed to fractions with a common denominator. Which face is most likely to tinish flat on the table? Find the uni of the four probabilities, What is the probability that face 3 does not finish flat or the table?A die has the shape of a tetrahedron. The lour faces are numbered 1, 2, 3 and 4. The die is thrown on the table. The probabilities of each of the four faces finishing liat on the table are as shown. - 1 2 3 1 Probability eila ine b Copy the table and till in the four empty boxes with the probabilities changed to fractions with a common denominator. Which face is most likely to tinish flat on the table? Find the uni of the four probabilities, What is the probability that face 3 does not finish flat or the table?

Answered by priyadharshini23
0

Answer:

since the oxidation state shown by an element of the second period is -2, no. of electrons in the outer most shell of this element is (8-2) = 6

Explanation:

the element is oxygen.

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