Question

The oxidation states of nitrogen in the following compounds HNO, NO, NO, NH, are
a) +4, +3, +2, +1 b) -3. +1, +2, +5 c) +3, +2, +1, 0
d) +5, +2, +1, -3
actatement​

Answer 1

Answer:

Hi . All the options are incorrect.

The actual series is :

= +1,+2,+2,-1

Hope it helps u . have a nice day. :)

Answer 2

$\red\bigstar$ Explanation $\red\bigstar$

$\leadsto$ Solution:-

i) HNO

Let the valency of N be x

As it is not an ion therefore the sum of the all valencies of each element in that atom/molecule will be equal to 0

Therefore,

+ 1 + x - 2 = 0

[Here the general valencues of H and O are +1 and -2 respectively]

x - 1 = 0

Therefore

$\boxed{Valency\:of\:Nitrogen\:is\:+1}$

ii) NO

Let the valency of N be x

As it is not an ion therefore the sum of the all valencies of each element in that atom/molecule will be equal to 0

Therefore,

x - 2 = 0

Therefore

$\boxed{Valency\:of\:Nitrogen\:is\:+2}$

iii) NO2

Let the valency of N be x

As it is not an ion therefore the sum of the all valencies of each element in that atom/molecule will be equal to 0

Therefore,

x + 2(-2) = 0

x - 4 = 0

Therefore

$\boxed{Valency\:of\:Nitrogen\:is\:+4}$

iv) NH

Let the valency of N be x

As it is not an ion therefore the sum of the all valencies of each element in that atom/molecule will be equal to 0

Therefore,

x + 1 = 0

Therefore

$\boxed{Valency\:of\:Nitrogen\:is\:-1}$