Chemistry, asked by funfrolic30, 7 hours ago

The oxidation states of Sulphur in SO3^2- ,S204^2- and S2O6^2- follows the order ?
please explain with a reason

1.S2O4^2- < SO3^2- 2.SO3^2- 3.S204^2- < S2O6^2- < SO3^2-
4.S206^2-

Answers

Answered by Anonymous
6

Answer:

explanation r in the attachment

The oxidation states of Sulphur in the anions SO3 2–, S2O4 2– and S2O6 2– follow the order :- (1) S2O6 2– < S2O4 –2 < SO3 2– (2) S2O4 2– < SO3 2– < S2O6 2– (3) SO3 2– < S2O4 2– < S2O6 2– (4) S2O4 –2 < S2O6 2– < SO3 2.

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