The P.E. of a spring is E,when it is stretched through 1cm.when streched through 2cm ,its P.E is
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Answered by
12
Hii friend,
We know the formula,
P.E of a spring = Kx²
F= Kx ²=> E......(1)
Now at the length of 2 cm
F= K×(4x²)
F= 4Kx²
F= 4E.
The resultant Potential energy will be 4E.
Hope this helps you a little!!!
We know the formula,
P.E of a spring = Kx²
F= Kx ²=> E......(1)
Now at the length of 2 cm
F= K×(4x²)
F= 4Kx²
F= 4E.
The resultant Potential energy will be 4E.
Hope this helps you a little!!!
ImmortalKiller:
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sorry
it is 1/2 kx2
1/2 kx square is the p.e.
and -kx is the force
OK no problem. The answer will be 4E
1/2 x (2)square
= 2
so the answer will remain 2E
Answered by
0
pE is kx
here x is displacement of spring
kx in first case k(1)= k
in second case k(2)=2k
here x is displacement of spring
kx in first case k(1)= k
in second case k(2)=2k
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