The P.I. of (D^2+1) y=cos〖3x 〗is *
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The auxiliary equation is (m^2 +1)^2 = 0.
The roots are +/- i , +/- i.
The imaginary roots are repeated.
Hence the Complementary Function (CF) is (c1+c2 x)cos x + (c3+c4 x)sin x.
The Particular Integral (PI) = [1/f(D)] cos 3x = [1/(D^2 +1)^2] cos 3x
Applying the [1/f(D^2)] cos ax = [1/f(-a^2)]cos ax
we get [1/64] cos 3x
Hence the complete solution is = CF +PI
= (c1+c2 x)cos x + (c3+c4 x)sin x + [1/64] cos 3x
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