Question

The P-V diagram of a system undergoing thermodynamic transformation is shown in figure. The work done by the system in going from A-B-C is 303 and 40heat is given to the system. The change in internal energy between A and Cis- PA C 40 T A​

Answer 1

Answer:

We know that 1cal=4.2J

Thus, heat absorbed=ΔQ=20cal=84J,

work done by the system=ΔW=−50J

From first law, change in internal energy ΔU=ΔQ−ΔW

⇒ΔU=84+50=134J