Question

the paint in a certain container is sufficient to paint an area equal to 9.375m2 . How many bricks of dimensions 22.5cm by 10cm by 7.5cm can be painted out of this container​

Answer 1

Answer:

• 100 Bricks can be painted by the paint in the container.

Explanation:

Given :

• Paint in the container that is sufficient to paint an area  = 9.375 m²
• Dimensions of Bricks are 22.5 cm × 10 cm × 7.5 cm

To find :

• Number of bricks that can be painted out of this container, n = ?

Solution :

• TSA of cuboid = 2 (  lb + bh + lh )

[ where l , b , h are length breadth and height of cuboid respectively ]

so,

→ TSA of each brick = 2 ( 22.5 × 10 + 10 × 7.5 + 22.5 × 7.5 )

→ TSA of each brick = 2 ( 225 + 75 + 168.75 )

→ TSA of each brick = 450 + 150 + 337.5

→ TSA of each brick = 937.5 cm²

Converting TSA given in cm² into m²

→ TSA of each brick = 937.5 × 100⁻² m²

→ TSA of each brick = 0.09375  m²

Now,

Finding number of bricks that could be painted

→ n = ( 9.375 ) / ( 0.09375 )

→ n = 100

therefore,

• 100 Bricks can be painted by the paint in the container.

Answer 2

Answer:

Total surface area of one brick = 2(lb + bh + hl)

= 2[(22.5×10) + (10×7.5) + (7.5×22.5)

= 2( 225 + 75 + 168.75)

= 2 × 468.75

= 937.5 m²

Let the number of bricks be 'n'

Area of 'n' bricks = 937.5n m²

Area that can be painted = 9.375 m²

= 93750 cm²

So, 93750 = 937.5n

93750/937.5 = n

100 = n

Thus, 100 bricks can be painted.