Question

The paint in a certain container is sufficient to paint an area
equal to 16.66 m2. How many bricks of dimensions 22cm,10cm and 8cm
can be painted out of this container? answer = (175)​

Answer 1

Answer:

Step-by-step explanation:

Given:

⇒Area=16.66m2

⇒22cm×10cm×8cm=l×b×h

⇒Total surface of cuboid (brick) =2(lb+bh+lh)

⇒2(22×10+10×8+22×8) cm2

=2×476=952 cm

⇒Area that can be painted by part of container =166600 cm2

⇒Let x number of bricks will be used.

⇒Area =952×x cm 2

⇒x= 166600/952 cm2

x = 175 cm2

​  

 

Answer 2

Answer :

›»› 175 bricks can be painted out of this container.

Given :

• The paint in a certain container is sufficient to paint an area equal to 16.66 m².
• The dimensions are 22 cm, 10 cm and 8 cm.

To find :

• How many bricks can be painted out of this container?

Solution :

• Area of painted = 16.66 m².
• Length = 22 cm.
• Breadth = 10 cm.
• Height = 8 cm.

Bricks are always are in the shape of cuboid.

As we know that

→ TSA of cuboid = 2(lb + bh + hl)

→ TSA of cuboid = 2(22 * 10 + 10 * 8 + 8 * 22)

→ TSA of cuboid = 2(220 + 80 + 176)

→ TSA of cuboid = 2(300 + 176)

→ TSA of cuboid = 2(476)

→ TSA of cuboid = 952 cm²

Converting the TSA of cuboid from cm² to m²,

→ 1 cm² = 10000 m²

→ 952 cm² = 952/10000

→ 0.0952 m²

So, The area of each brick = 0.0952 m².

Now,

→ Number of bricks that could be painted = Total area that can be painted by container ÷ Total surface of each brick.

→ 16.66 ÷ 0.0952

→ 16660000 ÷ 95200

→ 166600 ÷ 952

→ 175

Hence, 175 bricks can be painted out of this container.