Question

the paint in a certain container is sufficient to paint an area equal to 9.375 m^2.how many bricks of dimensions 22.5 cm into 10 cm into 7.5 CM can be painted out of this container

Answer 1

Total surface area of one brick = 2(lb + bh + lh)

= [2(22.5 ×10 + 10 × 7.5 + 22.5 × 7.5)] cm2

= 2(225 + 75 + 168.75) cm2

= (2 × 468.75) cm2

= 937.5 cm2

Let n bricks can be painted out by the paint of the container.

Area of n bricks = (n ×937.5) cm2 = 937.5ncm2

Area that can be painted by the paint of the container = 9.375 m2 = 93750 cm2

∴ 93750 = 937.5n

n = 100

Therefore, 100 bricks can be painted out by the paint of the container.

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

Total surface area of one brick = 2(lb + bh +lb)

= [2(22.5 × 10 + 10 × 7.5 + 22.5 × 7.5)] cm²

= 2(225 + 75 + 168.75) cm²

= (2 × 468.75) cm²

= 937.5 cm²

Let n bricks can be painted out by the paint of the container

Area of n bricks = (n × 937.5) cm2 = 937.5n cm²

As per given instructions, area that can be painted by the paint of the container = 9.375 m² = 93750 cm²

So we have, 93750 = 937.5n

n = 100

Therefore,

• 100 bricks can be painted out by the paint of the container.