Question

The paint in a certain container is sufficient to paint an area equal to 9.375 m2. How many bricks of dimensions 22.5 cm×10 cm×7.5 cm can be painted out of this container?

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Answer 1

Answer:

Volume of paint = 9.375 m2 = 93750 cm2

Dimension of brick = 22.5 cm×10 cm×7.5 cm

Total surface area of a brick = 2(lb + bh + lh) cm2

= 2(22.5×10 + 10×7.5 + 22.5×7.5) cm2

= 2(225 + 75 + 168.75) cm2

= 2×468.75 cm2 = 937.5 cm2

Number of bricks can be painted = 93750/937.5 = 100

HOPE THIS WILL HELP YOU

Answer 2

Given:-

• l = 22.5 cm
• b = 10 cm
• h = 7.5 cm

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$\sf \: Total \: surface \: area \: of \: one \: brick = 2(lb +bh+lb)$

$\sf \longrightarrow \: [2(22.5×10+10×7.5+22.5×7.5)] \: {cm}^{2}$

$\sf \longrightarrow \: 2(225+75+168.75) \: {cm}^{2}$

$\sf \longrightarrow \: (2×468.75) \: {cm}^{2}$

$\sf \longrightarrow \: 937.5 \: {cm}^{2}$

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Let n bricks can be painted out by the paint of the container.

Area of n bricks = (n×937.5) cm² = 937.5n cm2

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As per given instructions, area that can be painted by the paint of the container = 9.375 m² = 93750 cm²

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So, we have, 93750 = 937.5n

n = 100

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Therefore, 100 bricks can be painted out by the paint of the container.