the paint in a certain container is sufficient to paint on area equal to 9.375 metre square. how many bricks of dimension 22.5 centimetre 10 cm and 7.5 CM can be painted out of this container ?
Answers
Answer:
Surface area of a solid object is a measure of the total area that the surface of the object occupies and it is always measured in square unit.
Hence surface area is also known as total surface area TSA.
Given:
Dimension of brick = l=22.5 cm, b=10 cm, c=7.5 cm
Total surface area of a container= 9.375 m²
Total surface area of a brick = 2(lb + bh + lh)
= 2(22.5×10 + 10×7.5 + 22.5×7.5)
= 2(225 + 75 + 168.75)
= 2×468.75
= 937.5 cm²
= 937.5/100×100 m²
Number of bricks that painted out of this container= total area painted by containers paint / total surface area of a brick
=9.375/ (937.5/100×100)
=( 9.375×100×100) / 937.5
= 937500/ 9375= 100
Hence,100 bricks can be painted out.
Question:
The paint in a certain container is sufficient to paint on area equal to 9.375 m². How many bricks of dimension 22.5 cm, 10 cm and 7.5 cm can be painted out of this container ?
Answer:
The number of bricks can be painted out of this container is 100.
Given:
The paint in the container is sufficient to paint on area equal to 9.375 m².
The dimension of each brick is 22.5 cm, 10 cm and 7.5.
To find:
The number of bricks can be painted with the paint of the container.
Explanation:
The paint in the container is sufficient to paint on area equal to 9.375 m².
= (9.375× 10000) cm² [∵ 1 m² = 10000 cm².]
= 93750 cm².
The dimension of each brick is 22.5 cm, 10 cm and 7.5.
We know that,
Surface area of a cuboid = 2 ( Length× Bread + Breadth×Height + Height×Lenght)
∴ The surface area of each brick _
2×(22.5×10+10×7.5+ 22.5×7.5) cm²
= 2× (225 + 75 + 168.75)
= 2 × 468.75
= 937.5 cm².
∴ The number of bricks can be painted with the paint of the container_
( Total area can be painted by the paint ÷ Surface area of each brick)
= (93750 ÷ 937.5)
= 100 bricks.
∴ 100 bricks can be painted with the paint of the container.