Question

the paint in a container is sufficient to paint 7.2m^2surface .how many containers of paint will be required to paint walls of a room with dimensions 3.2m×2.7m×2.4m .find the cost of paint,if each container costs 460.
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Answer 1

AnswEr :

$\bf{ Given}\begin{cases}\text{Dimensions : ( 3.2 m \times 2.7 m \times 2.4 m)} \\\text{One Paint Container can Paint 7.2 \:{ \text m}^{2} }\\\text{One Paint Container costs Rs. 460}\\ \text{Find \:the Cost of Paining of walls of room.}\end{cases}$

We Have to Paint walls of Room Only, for that we will find CSA (Curved Surface Area)

• Curved Surface Area of the Room :

$\longrightarrow \tt CSA = 2(Length + Breadth) \times Height \\ \\\longrightarrow \tt CSA = 2(3.2m + 2.7m) \times 2.4m \\ \\\longrightarrow \tt CSA = 2 \times 5.9m \times 2.4m \\ \\\longrightarrow \blue{\tt CSA = 28.32\:{m}^{2}}$

$\rule{300}{1}$

• Number of Container Required :

$\longrightarrow \footnotesize\text{Number of Container \times One Container Efficiency = CSA} \\ \\\longrightarrow \text{Number of Container \times 7.2\:{\text m}^{2} =28.32\:{\text m}^{2} } \\ \\\longrightarrow \text{Number of Container = \cancel\dfrac{28.32 \:{\text m}^{2}}{7.2 \:{\text m}^{2}} } \\ \\\longrightarrow \red{\text{Number of Container \approx4 }}$

$\rule{300}{1}$

• Total Cost of Painting of Walls :

⇒ Cost = No. of Containers × Rate

⇒ Cost = 4 × Rs. 460

⇒ Cost = Rs. 1840

⠀

∴ Cost of Painting of walls is Rs. 1840

#answerwithquality #BAL

Answer 2

$\bf{\Huge{\underline{\boxed{\bf{\blue{ANSWER\::}}}}}}$

$\bf{\Large{\underline{\bf{Given\::}}}}}$

The paint in a container is sufficient to paint is 7.2m² surface.The dimensions of the room is 3.2m × 2.7m × 2.4m. If each container costs Rs.460.

$\bf{\Large{\underline{\bf{To\:find\::}}}}}$

The containers of paint will be required to paint walls of room & the cost of paint.

$\bf{\Large{\underline{\bf{\orange{Explanation\::}}}}}$

$\bf{We\:have\begin{cases}\sf{The\:paint\:in\:a\:container\:is=7.2m^{2} }\\ \sf{The\:dimensions\:of\:the\:room=3.2m*2.7m*2.4m}\\ \sf{The\:cost\:of\:paint\:of\:each\:container=Rs.460}\end{cases}}$

Area of four wall of room,we get;

We know that formula of the curved surface area of room:

⇒ 2h(l + b) [sq.units]

Therefore,

• Length of the room,[l] = 3.2m
• Breadth of the room,[b] = 2.7m
• Height of the room,[h] = 2.4m

⇒ 2(2.4)(3.2+2.7)m²

⇒ (4.8 × 5.9)m²

⇒ 28.32m²

Hence, The curved surface area of room is 28.32m².

&

→ Number of container = $\bf{\frac{Curved\:surface\:area\:of\:room}{Area\:than\: can\: be \:painted \:by \:container} }$

→ Number of container = $\bf{\frac{28.32*100m^{2} }{7.2*100m^{2} } }$

→ Number of container = $\bf{\cancel{\frac{2832}{720} m^{2} }}$

→ Number of container = 3.93

→ Number of container = 4  [approximately]

Thus,

The 4 container required to paint the walls of room.

Now,

• $\bf{\Large{\underline{\bf{\green{The\:cost\:of\:paint\::}}}}}$

→ Each container cost is Rs.460

→ 4 container cost is Rs.(4×460)

→ 4 container cost is Rs.1840.