Question

the pair of co incident lines in the following are *

x-2y=0 and 3x+4y=20
2x+3y=9 and 4x+6y=18
x+2y=4 and 2x+4y=12
x+y=8 and x-y=4​

Answer 1

Answer:

(A) one solution

For the given pair of equations x−2y=0 and 3x+4y=20;

a

2

a

1

=

3

1

c

2

b

1

=

4

−2

=

2

−1

c

2

c

1

=

−20

0

=0

As the given pair of linear equation satisfies

a

2

a

1



=

b

2

b

1

,

The graph will be a pair of lines intersecting at a unique point, which is the solution of the pair of equations.