Question

The pair of compounds in which both the metals are in the highest possible oxidation state is

(1) FeSO₄, CuS₂
(2) CrO₂Cl₂, MnO₄⁻
(3) TiO₂, MnO₂
(4) [Co(CN)₆]³⁻, MnO₃

✭ Answer with explaination!​

Answer 1

Answer:  CrO₂Cl₂, MnO₄⁻

Answer 2

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Option 2) CrO2Cl2,MnO4 is correct answer.

REASON

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refer attachment.

MORE TO KNOW. .

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The sum of the oxidation states of all of the atoms needs to equal the total charge on the ion.

The sum of the oxidation states of all of the atoms needs to equal the total charge on the ion.For example, for NH4+, if each hydrogen atom has an oxidation state of +1, and the overall charge is +1, then we can solve for the oxidation state of nitrogen:

The sum of the oxidation states of all of the atoms needs to equal the total charge on the ion.For example, for NH4+, if each hydrogen atom has an oxidation state of +1, and the overall charge is +1, then we can solve for the oxidation state of nitrogen:4(+1)+OSNOSNOSN=+1=+1−4(+1)=−3

The sum of the oxidation states of all of the atoms needs to equal the total charge on the ion.For example, for NH4+, if each hydrogen atom has an oxidation state of +1, and the overall charge is +1, then we can solve for the oxidation state of nitrogen:4(+1)+OSNOSNOSN=+1=+1−4(+1)=−3Similarly, we can do SO42−. If each oxygen atom has an oxidation state of -2, and the overall charge is -2, we can solve for the oxidation state of sulfur:

The sum of the oxidation states of all of the atoms needs to equal the total charge on the ion.For example, for NH4+, if each hydrogen atom has an oxidation state of +1, and the overall charge is +1, then we can solve for the oxidation state of nitrogen:4(+1)+OSNOSNOSN=+1=+1−4(+1)=−3Similarly, we can do SO42−. If each oxygen atom has an oxidation state of -2, and the overall charge is -2, we can solve for the oxidation state of sulfur:4(−2)+OSSOSSOSS=−2=−2−4(−2)=+6