the pair of equation x+3y+5=0 and -3x-9y+12=0 has
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Answer:
ax+by=a-b
ax=a-b-by
x=a-b-by/a←
bx-ay=a+b
substituting
b(a-b-by/a)-ay=a+b
ab-b²-b²y/a-ay=a+b
ab-b²-b²y-a²y/a=a+b
ab-b²-(b²+a²)y=a²+ab
-(b²+a²)y=a²+ab-ab+b²
(b²+a²)y=-(a²+b²)
y=-(a²+b²)/a²+b²
y=-1←
substituting value of y
x=a-b-b(-1)/a
x=a-b+b/a
x=a/a
x=1
Step-by-step explanation:
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