Question

The pair of equations 3x+2y=8 and 2x + y =5 has a unique solution then the value of x and y are
(a) x=1, y=2 (b) x=2, y=1 (c) x=3, y= 1 (d) x=1, y= 3​

Answer 1

Answer:

b) x=2 ,y=1

Step-by-step explanation:

let 3x+2y=8 is ist equation and 2x+y=5 is 2nd equation

multiply 2nd equation by 2

4x+2y=10 -3rd equation

subtracting ist from 3rd we have

4x+2y=10

-(3x+2y=8)

x =2

hence put in ist equation

3(2)+2y=8

6+2y =8

2y=2

y=1

Answer 2

Step-by-step explanation:

b) x=2 ,y=1

Step-by-step explanation:

let 3x+2y=8 is ist equation and 2x+y=5 is 2nd equation

multiply 2nd equation by 2

4x+2y=10 -3rd equation

subtracting ist from 3rd we have

4x+2y=10

-(3x+2y=8)

x =2

hence put in ist equation

3(2)+2y=8

6+2y =8

2y=2

y=1