Math, asked by pitambermajhi432, 6 months ago

The pair of equations 3x+4y=10 and 2x-2y=2 has how many solution

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Answered by srikanthn711

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$1)i)3x + 4y = 10 \\ = > 3(2) +4y = 10 \\ = > 6 + 4y = 10 \\ = > 4y = 10 - 6 \\ = > 4y = 4 \\ = > y = \frac{4}{4} \\ = > y = 1 \\ \\ ii) 3x + 4(2) = 10 \\ = > 3x + 8 = 10 \\ = > 3x = 10 - 8 \\ = > 3x = 2 \\ = > x = \frac{2}{3} \\ = > x = 0.7$

$2)i)2x - 2y = 2 \\ = > 2(2) - 2y = 2 \\ = > 4 - 2y = 2 \\ = > 2y = 2 + 4 \\ = > 2y = 6 \\ = > y = \frac{6}{2} \\ = > y = 3 \\ \\ ii)2x - 2(3) = 2 \\ = > 2x - 6 = 2 \\ = > 2x = 2 + 6 \\ = > 2x = 8 \\ = > x = \frac{8}{2} \\ = > x = 4$

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Answered by Anonymous

Answer:

$$\begin{lgathered}1)i)3x + 4y = 10 \\ = > 3(2) +4y = 10 \\ = > 6 + 4y = 10 \\ = > 4y = 10 - 6 \\ = > 4y = 4 \\ = > y = \frac{4}{4} \\ = > y = 1 \\ \\ ii) 3x + 4(2) = 10 \\ = > 3x + 8 = 10 \\ = > 3x = 10 - 8 \\ = > 3x = 2 \\ = > x = \frac{2}{3} \\ = > x = 0.7\end{lgathered}$$

$$\begin{lgathered}2)i)2x - 2y = 2 \\ = > 2(2) - 2y = 2 \\ = > 4 - 2y = 2 \\ = > 2y = 2 + 4 \\ = > 2y = 6 \\ = > y = \frac{6}{2} \\ = > y = 3 \\ \\ ii)2x - 2(3) = 2 \\ = > 2x - 6 = 2 \\ = > 2x = 2 + 6 \\ = > 2x = 8 \\ = > x = \frac{8}{2} \\ = > x = 4\end{lgathered}$$

$$\begin{lgathered}\\ \\\end{lgathered}$$

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The pair of equations 3x+4y=10 and 2x-2y=2 has how many solution​

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The pair of equations 3x+4y=10 and 2x-2y=2 has how many solution