Question

The pair of equations 9x + 4y= 9 and 7x + Ky = 5 has no solution then, K=​

Answer 1

AnsWer :

k = 28/9.

Solution :

Condition have, ( No solution )

• a1 /a2 = b1 / b2 ≠ c1 /c2.

A/Q,

$\tt\dagger \: \: \: \: \: 9x + 4y= 9. \: \: \: \: \:-(1)$

$\tt\dagger \: \: \: \: \: 7x + Ky = 5. \: \: \: \: \:-(2)$

Where as,

• a1 = 9.
• a2 = 7
• b1 = 4.
• b2 = k.
• c1 = 9.
• c2 = 5.

$\tt : \implies\frac{9}{7} = \frac{4}{k} \neq \frac{9}{5}$

Case 1.

$\tt : \implies\frac{9}{7} = \frac{4}{k}$

$\tt : \implies \frac{9}{4 \times 7} = k.$

$\tt : \implies k = \frac{28}{9}$

Case 2.

$\tt : \implies \frac{4}{k} \neq \frac{9}{5}$

$\tt : \implies k \neq \frac{20}{9}$

Therefore, the Value of k = 28 /9.

Some Information :

Many Solution.

• a1 /a2 = b1 / b2 = c1 /c2.

No Solution.

• a1 /a2 = b1 / b2 ≠ c1 /c2.

Unique Solution.

• a1 /a2 ≠ b1 / b2.

Answer 2

Answer:

Given equation have no solution if

à/á=b^1/b^2=\c^1lc^2

9/7=4/k=/9/5

9/7=4/k

k=28/9