Question

The pair of equations x + 2y – 5 = 0 and −3x – 6y + 15 = 0 have
(a) A unique solution (b) Exactly two solutions
(c) Infinitely many solutions (d) No solution

Answer 1

Answer:

c)

Infinitely many solutions

Answer 2

Answer:

Option (C) infinite many solution.

Solution :-

The given equations are :

• x + 2y - 5 = 0
• -3x - 6y + 15 = 0

From the given equation we have :

$↦</p><p></p><p> \bold{\frac{a1}{a2} = \frac{x}{ - 3x} = \frac{1}{ - 3}}$

$↦ \bold{ \frac{b1}{b2} = \frac{2y}{ - 6y} = \frac{1}{ - 3}}</p><p></p><p>$

$↦ \bold{ \frac{c1}{c2} = \frac{ - 5}{15} = - \frac{1}{3}}$

Hence;

$\bold\red{ \frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}}$

Therefore The Given Pair of lines have Infinity many solution.