Question

The pair of equations x+2y-5-0 and -4-8y+20-0 have

(a) Unique solution (b) exactly two solutions (c) infinitely many solutions​

Answer 1

Answer:

(d) no solution

Step-by-step explanation:

I hope this will help you

Answer 2

Answer:

(c) Infinite many solutions

Step-by-step explanation:

We have two linear equations

a1x + b1y + c1 = 0

a2x + b2y + c2 = 0

• Condition for exactly one solution= a1/a2 ≠b1/b2

• Condition for infinite solutions =a1/a2 = b1/b2 = c1/c2

• Condition for no solution = a1/a2 = b1/b2 ≠c1/c2

The given equations are:

x + 2y - 5 = 0  ......................(1)

-4x - 8y + 20 = 0

Or, 4x + 8y - 20 = 0

Dividing it by 4 we get

x + 2y - 5 = 0    ..........................(2)

a1/a2 = b1/b2 = c1/c2

1/1 = 2/2 = -5/-5

We observe that both the equations are same

Thus, the pair of equations will have infinitely many solutions.